How to calculate inductance of the coil

How to calculate inductance of the coil

The coil of inductance is capable to accumulate magnetic energy at course of electric current. Its main characteristic is its inductance which is designated by letter L and is measured in Henry (Gn). The inductance of the coil depends on its features.

It is required to you

  • material of the coil and its geometrical parameters

Instruction

1. The inductance of the coil is proportional to the linear sizes of the coil, magnetic permeability of the core and a square of number of rounds of winding. The inductance of the coil which is reeled up on the toroidal core is equal: L =? 0 *? r*s * (N^2)/l. In this formula? 0 — a magnetic constant which is approximately equal 1.26*(10^-6) of Gn/m? r is relative magnetic permeability of material of the core which depends from frequency), s is the cross-sectional area of the core, l there is length of the average line of the core, N is number of rounds of the coil. Relative magnetic permeability and material and also number of rounds of N are dimensionless sizes.

2. Thus, the inductance of the coil of subjects is more, than the area of its section is more. This condition increases a magnetic flux via the coil at the same current in it. The inductance of the coil of inductance in mkgn can be calculated also by a formula: L = L0*(N^2)*D*(10^-3). Here N is number of rounds, D - diameter of the coil in centimeters. The coefficient of L0 depends on the coil length relation to its diameter. For the single-layer coil it is equal: L0 = 1 / (0.1 * (l/D) +0.45)).

3. If in a chain of the coil are connected consistently, then their general inductance is equal to the sum of induktivnost of all coils: L = If coils are connected (L1+L2+...+Ln) in parallel, then their general inductance is equal: L = 1/((1/L1)+(1/L2)+... + (1/Ln))

Author: «MirrorInfo» Dream Team


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