Sphere call the simplest volume figure of geometrically correct form which all points of space in borders are removed from its center on the distance which is not exceeding radius. The surface formed by a set of the points, most remote from the center, is called the sphere. Parameter which is called sphere volume is intended for quantitative expression of a measure of the space concluded in the sphere.
Instruction
1. If it is required to measure sphere volume not theoretically but only make-shifts, then it is possible to make it, for example, having determined the volume of the water which is forced out by it. This way is applicable when is an opportunity to place a sphere in any capacity proportional to it - a graduated cylinder, a glass, to bank, a bucket, a barrel, the pool, etc. In this case before the room of a sphere note water level, make it repeatedly after its full immersion, and then find the difference between marks. Usually measured capacity of factory production has the divisions showing volume in liters and units, derivative of it, - milliliters, decalitres, etc. If the received value has to be transferred to cubic meters and multiple to it units of volume, then you recognize that one liter corresponds to one cubic decimeter or one thousand share of cubic meter.
2. If material of which the sphere is made is known, and density of this material can be learned, for example, from the reference book, then it is possible to determine volume having weighed this subject. Just divide result of weighing into the help density of substance of production: V=m/p.
3. If the radius of a sphere is known from statements of the problem or it can be measured, then for calculation of volume it is possible to use the corresponding mathematical formula. Increase quadruple number of Pi by the third degree of radius, and divide the received result into the three: V=4*π*r³/3. For example, at radius in 40 cm the volume of a sphere will be 4*3.14*40³/3 = 267946.67 cm³ ≈ 0.268 m³.
4. To measure diameter happens more simply more often, than radius. In this case there is no need to halve it for use with a formula from the previous step - better to simplify a formula. According to the transformed formula increase Pi's number by diameter in the third degree, and divide result into the six: V=π*d³/6. For example, the sphere with a diameter of 50 cm has to have volume in 3.14*50³/6 = 65416.67 cm³ ≈ 0.654 m³.