At the solution of physical tasks all sizes are given to one measuring system. As a rule, at the same time the IS (international system) system is used. It allows to use only numerical values of physical quantities in the course of calculations. However in practice often it is necessary to translate each other pretty diverse physical quantities, for example, to transfer kg/h to m3/h.
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- calculator
Instruction
1. To transfer kg/h to m3/h, it is necessary to specify substance density, the flow (stream) of which is measured in this task. Very often water or low-concentrated solutions appears in school tasks and in practice. In this case density of liquid it is possible to accept equal 1000 kg/m3 (kilogram on cubic meter). That is, to translate the water consumption set in kg/h on m3/h use the following formula: R (m3/h) = P (kg/h) / 1000, where: R (m3/h) – a liquid consumption in m3/chr (kg/h) – the known consumption of liquid expressed in kg/h.
2. PrimerPotreblenie of the cooling water in the tiny liquid circulating Petite Fleur w thermostat - 23 kg/h. Question: what volume of water uses the device for one hour of work? Decision: 23/1000=0.023 (m3/h).
3. If the liquid considered in a task is easier or heavier than water, then find its density in the corresponding tables of density. If there are no necessary tables or the name of liquid is unknown or it represents mix of several substances in an unknown proportion, then determine liquid density independently. After density of liquid becomes known, use the following formula: R (m3/h) = P (kg/h) / P, where P – the liquid density expressed in kg/m3.
4. PrimerZa one hour of work the fuel-dispensing column gives 2700 kg of gasoline. Question: how many cubic meters of gasoline can the gas station within an hour download? Decision: 1. Find in the table of density of fuel and lubricants gasoline density – 750 kg/m³.2. Calculate a gasoline consumption by the above-stated formula: 2700 / 750 = 3.6 (m3/h).
5. If liquid consumption speed in kg/h is unknown, then measure it independently. For this purpose at all it is optional to arm with huge measured capacity and Take any rather big container to fill it the whole hour and weigh it. Then fill it within 5-10 minutes. Then write down filling time, weigh the filled capacity and subtract container weight from this weight. Divide the mass of liquid (in kg) for the period of filling (in hours). As a result liquid consumption speed in kg/h will turn out.
6. If density of liquid is unknown, then pour it in the standard capacity of the known volume (a bucket, a flask, to bank, etc.). Having divided the mass of liquid (in kg) into volume (in m³), receive value of density in kg/m³.