Spiral staircases are used in those houses where it is necessary to save room volume. To build such design independently simply, it is much more difficult to calculate it correctly.
Instruction
1. Stock up with drawings and make calculation. For example, you want to construct ladder where S=0.8m width, and height N=3m. First of all, define value of the general diameter of D. For this purpose the double width of march should be put with diameter of the main basic column. If the center basic column 0.2 m thick, then this spiral staircase has diameter of D=2xS+b=2xO, 8+0.2=1.8 m.
2. Take squared paper. From the center of cloth describe the line of circle with R=D radius: 20.9 m in which it is necessary to enter the column having the radius of = 0.1 m. Further on R1S radius: 2+r=O, 8:2+0.1=0.5 m describe other circle. It on the plan of spiral staircase is the projected line of vskhod.
3. Now it is necessary to define number of steps of n which will be located on one ladder round. For this purpose separate length of circle into parts which are equal to the necessary width of step of s on the line of vskhod up. For example. If to take for length of steps in the area of vskhod s=0.2m value, then number n = 2xPR1: s = 2x3,14x0,5:0,2 = 15.
4. Separate the received circle into n (in this case this number 15, quantity of steps) and draw radial lines from the center to n to parts. The person has to come downstairs and rise freely and not to touch with the head inside of steps over him. For this purpose small excess becomes. If, for example, growth going on ladder is equal 1.9, then to this growth it is necessary to add stock and thickness of steps still. According to 0.2 m and 0.0 5 m taking into account that steps will be made of "the fiftieth board".
5. It turns out N1=1.9+0.2+0.05=2.15m. Height of one step of h will turn out division of height of full round into number n. As a result of h= H1: n=2.15:15=0.14m.
6. Determine number of all steps of ladder by division of height into height of one step. Total number if, n=21 turns out H=3. While the number of all treads will equal n — 1=21 — 1 =20. Compensate missing width in tread when you arrange overhang of steps. But they have to act no more, than on 0.09 m.