At a research of square function which schedule is the parabola it is necessary to find parabola top coordinates in one of points. How to make it analytically, using the equation set for a parabola?
Instruction
1. Square function is a function of a look y=ax^2+bx+c where a - the senior coefficient (it surely has to be nonzero), b - younger coefficient, with - the free member. This function gives the schedule a parabola which branches are directed or up (if a> 0), or down (if and <0). At a=0 the square function degenerates in linear function.
2. Let's find parabola top x0 coordinate. It is on formulex0=-b/a.
3. y0=y(x0). To find parabola top y0 coordinate, it is necessary in function instead of x to substitute the found x0 value. Count what y0 is equal to.
4. Coordinates of top of a parabola are found. Write down them in the form of coordinates of one point (x0, y0).
5. At creation of a parabola you remember that it is symmetric concerning an axis of symmetry of the parabola passing vertically through parabola top since square function is even. Therefore it is enough to construct only one branch of a parabola on points, and to complete another symmetrically.