Oxygen – the major for activity of the person and all living organisms an element of the table of Mendeleyev. Represents itself the gas which does not have color, taste and a smell, heavier than air. A chemical formula of oxygen – O2. The strongest oxidizer conceding on activity only to fluorine and chlorine reacts with the vast majority of elements, forming oxides. It is widely used in metallurgy, chemistry, agriculture, medicine and also as a component of rocket fuel (as oxidizer). How to determine oxygen volume?
Instruction
1. Let's assume, you know the number of moles of oxygen (for example, 5). You are faced by a question: what volume is occupied under normal conditions by these 5 moths? The decision will be such: under normal conditions volume 1 asking any gas is a constant and it is equal about 22.4 liters. Therefore, 5 moths of oxygen under normal conditions will occupy volume 22.4*5 = 112 liters.
2. And if the mass of oxygen is known to you? Let's assume, 96 grams. What volume will they occupy under normal conditions? At first learn how many moths of oxygen contain in 96 grams of this substance. The molar mass of oxygen (proceeding from formula O2) = 32 grams/mol. Therefore, 96 grams are 3 asking. Having made multiplication, receive the following answer: 22.4*3 = 67.2 liters.
3. And if you have to determine oxygen volume under the conditions other than normal? Here you will be come to the rescue by the universal equation of Mendeleyev-Klapeyrona describing a condition of so-called "ideal gas". It registers in such look: PV = RTM/m, where P – gas pressure in pascals, V – its volume in liters, R – a universal gas constant, T – gas temperature in degrees Kelvin, M – the mass of gas, m – its molar weight.
4. Transforming the equation, receive: V = RTM/mP.
5. As you can see, if you have data, necessary for calculations (temperature, the weight and pressure of oxygen), it is very simple to calculate its volume. As R (8.31) and m (32) values are already known to you.