That on the card or the area it was always possible to find some object, the international system of coordinates including the width and longitude was created. The ability sometimes determine the coordinates can even save life, for example, if you got lost in the forest and want to transfer information on the location to rescuers. Width defines the corner formed by the steep line from the equator and the necessary point. If the place is located to the north of the equator (above), then latitude will be northern if to the south (below) - southern.
It is required to you
- - protractor and plumb;
- - hours;
- - nomogram;
- - card;
- - the computer connected to the Internet.
Instruction
1. Width defines the corner formed by the steep line from the equator and the necessary point. If the place is located to the north of the equator (above), then latitude will be northern if to the south (below) - southern. To learn width in field conditions by means of make-shifts, take a protractor and a plumb. If you have no protractor, make it of two rectangular levels, having fastened them in the form of compasses in the way that it was possible to change a corner between them. Fix thread with cargo in the center, it will play a plumb role. Guide the protractor basis at a pole star. Then between a plumb and a protractor subtract 90 from a corner?. As an angular deviation from a world pole axis at a polar zveda on only 1?, the corner between the horizon and a pole star will be equal to the latitude of the place so safely calculate this corner and, thus, width.
2. If you have hours, mark day length between rising and sunset. Take the nomogram, in the left part postpone the received day length, and in the right part celebrate date. Connect the received values and define a point of intersection with a middle part. It will also be the width of your location.
3. To determine width by the card, use horizontal lines – parallels. Look, on the right and at the left each line has a value in degrees. If the required place lies directly on the line, width will be equal to this value. If you look for the latitude of the place located between two lines count approximately at what distance it is located from the next parallel. For example, the point is located approximately in 1/3 from a parallel 30? and 2/3 from 45?. Means, approximately its width will be equal to 35?.